The phosphorous containing compound produced in the reaction of `P_(4)O_(6)` with `H_(2)O_` is

Options

A. `H_(3)PO_(4)`
B. `H_(3)PO_(2)`
C. `H_(3)PO_(3)`
D. `H_(3)PO_(5)`

Answer

To determine the phosphorus-containing compound produced when \( P_4O_6 \) reacts with \( H_2O \), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are phosphorus trioxide (\( P_4O_6 \)) and water (\( H_2O \)).

### Step 2: Write the Reaction
When \( P_4O_6 \) reacts with water, the general reaction can be written as:
\[ P_4O_6 + H_2O \rightarrow ? \]

### Step 3: Determine the Product
Phosphorus trioxide reacts with water to form phosphorous acid. The chemical formula for phosphorous acid is \( H_3PO_3 \).

### Step 4: Balance the Reaction
To balance the reaction, we can write:
\[ P_4O_6 + 6H_2O \rightarrow 4H_3PO_3 \]
This indicates that one mole of \( P_4O_6 \) reacts with six moles of water to produce four moles of \( H_3PO_3 \).

### Step 5: Conclusion
The phosphorus-containing compound produced in the reaction of \( P_4O_6 \) with \( H_2O \) is \( H_3PO_3 \).

### Final Answer
The correct option is \( H_3PO_3 \).

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