Reaction of zinc with cold and dilute nitric acid yields

Options

A. `Zn(NO_(3))_(2)+N_(2)O`
B. `Zn(NO_(3))_(2)+NO`
C. `Zn(NO_(3))_(2)+NH_(4)NO_(3)`
D. `Zn(NO_(3))_(2)+NO_(2)`

Answer

To solve the question regarding the reaction of zinc with cold and dilute nitric acid, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Zinc (Zn)
- Cold and dilute nitric acid (HNO3)

### Step 2: Write the Reaction
When zinc reacts with cold and dilute nitric acid, it undergoes a redox reaction. The nitric acid acts as an oxidizing agent. The balanced chemical equation for this reaction can be written as:

\[ \text{Zn} + 4 \text{HNO}_3 \rightarrow \text{Zn(NO}_3\text{)}_2 + \text{NH}_4\text{NO}_3 + 2 \text{H}_2\text{O} \]

### Step 3: Identify the Products
From the balanced equation, we can identify the products formed:
- Zinc nitrate (Zn(NO3)2)
- Ammonium nitrate (NH4NO3)
- Water (H2O)

### Step 4: Conclusion
Thus, the reaction of zinc with cold and dilute nitric acid yields:
- Zinc nitrate (Zn(NO3)2)
- Ammonium nitrate (NH4NO3)
- Water (H2O)

### Final Answer
The correct answer is:
**Zinc nitrate (Zn(NO3)2), Ammonium nitrate (NH4NO3), and Water (H2O)**.