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Amongst H(2)O, H(2)S, H(2)Se and H(2)Te,...

Amongst `H_(2)O, H_(2)S, H_(2)Se and H_(2)Te`, the one with the highest boiling point is

A

`H_(2)O` because of hydrogen bonding

B

`H_(2)Te` because of higher molecular weight

C

`H_(2)S` because of hydrogen bonding

D

`H_(2)Se` because of lower molecular weight

Text Solution

Verified by Experts

The correct Answer is:
A

The order of boiling point of hydride of oxygen family is `H_(2)O gt H_(2)Te gt H_(2)Se gt H_(2)S`
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