Sulphur on boiling with `NaOH` solution gives

Options

A. `Na_(2)S_(2)O(3) + NaSO_(3)`
B. `Na_(2)S_(2)O_(3) + Na_(2)S`
C. `Na_(2)SO_(3) + H_(2)S`
D. `Na_(2)SO_(3) + SO_(2)`

Explanation

To solve the question, "Sulphur on boiling with NaOH solution gives?", we will analyze the reaction between sulphur and sodium hydroxide (NaOH) step by step.

### Step 1: Identify the Reactants
The reactants in this reaction are sulphur (S) and sodium hydroxide (NaOH).

### Step 2: Understand the Reaction
When sulphur is boiled with sodium hydroxide, a chemical reaction occurs. This reaction typically leads to the formation of sodium thiosulphate (Na2S2O3) and sodium sulphide (Na2S).

### Step 3: Write the Chemical Equation
The balanced chemical equation for the reaction is:
\[ \text{S} + 2 \text{NaOH} \rightarrow \text{Na2S2O3} + \text{Na2S} + \text{H2O} \]
However, for simplicity, we can focus on the main products formed:
\[ \text{S} + 2 \text{NaOH} \rightarrow \text{Na2S2O3} + \text{Na2S} \]

### Step 4: Identify the Products
From the reaction, we can see that the products formed are:
- Sodium thiosulphate (Na2S2O3)
- Sodium sulphide (Na2S)

### Step 5: Conclusion
Thus, when sulphur is boiled with sodium hydroxide, it gives sodium thiosulphate and sodium sulphide.

### Final Answer
The correct option for the given question is:
**Na2S2O3 + Na2S** (Option B)

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