`4AgNO_(3) + 2H_(2)O + H_(3)PO_(2) overset("boil")rarr 4 Ag + 'X' + 'Y'`
If X is oxyacid of nitrogen and Y is oxyacid of phosphorous then correct statement(s) is/are

Options

A. X is `HNO_(2)`
B. Y is `H_(3)PO_(4)`
C. Y is `H_(3)PO_(2)`
D. X is `HNO_(3)`

Explanation

To solve the given question, we need to analyze the reaction provided:

**Given Reaction:**
\[ 4 \text{AgNO}_3 + 2 \text{H}_2\text{O} + \text{H}_3\text{PO}_2 \overset{\text{boil}}{\rightarrow} 4 \text{Ag} + X + Y \]

### Step 1: Identify the Reactants and Products
In this reaction:
- **Reactants:** Silver nitrate (\( \text{AgNO}_3 \)), water (\( \text{H}_2\text{O} \)), and phosphorous acid (\( \text{H}_3\text{PO}_2 \)).
- **Products:** Silver metal (\( \text{Ag} \)), and two unknown compounds \( X \) and \( Y \).

### Step 2: Determine the Nature of X and Y
- **X** is specified to be an oxyacid of nitrogen.
- **Y** is specified to be an oxyacid of phosphorus.

### Step 3: Analyze the Reaction
When silver nitrate reacts with phosphorous acid and water, the following transformations occur:
1. Silver nitrate decomposes to form silver metal.
2. The nitrogen in silver nitrate can be oxidized to form nitric acid (\( \text{HNO}_3 \)).
3. Phosphorous acid can further react to form phosphoric acid (\( \text{H}_3\text{PO}_4 \)).

### Step 4: Identify X and Y
Based on the analysis:
- **X** (an oxyacid of nitrogen) is identified as nitric acid (\( \text{HNO}_3 \)).
- **Y** (an oxyacid of phosphorus) is identified as phosphoric acid (\( \text{H}_3\text{PO}_4 \)).

### Conclusion
Thus, the products of the reaction are:
- \( X = \text{HNO}_3 \)
- \( Y = \text{H}_3\text{PO}_4 \)

### Final Answer
The correct statements are:
- \( Y \) is \( \text{H}_3\text{PO}_4 \) (Statement B).
- \( X \) is \( \text{HNO}_3 \) (Statement D).