In the given reaction `{:(" "CH_(3)),(" |"),(H_(3)C-C-C-CHO),(" | ||"),(" "H_(3)C " "O):} overset("(i)Conc. NaOH")underset((ii)H^(+)) to` product is

Options

A. `{:(" "H),(" |"),(H_(3)C-C-C-CH_2-OH),(" | ||"),(" "H_(3)C " "O):}`
B. `{:(" "CH_(3)),(" |"),(H_(3)C-C-CH-COOH),(" | |"),(" "H_(3)C " "OH):}`
C. `{:(" "CH_(3)),(" |"),(H_(3)C-C-C-COOH),(" | ||"),(" "H_(3)C " "OH):}`
D. `{:(" "CH_(3)" "OH),(" | |"),(H_(3)C-C-C-CH_2),(" | ||"),(" "H_(3)C " "OH):}`

Answer

To solve the given reaction step by step, we will analyze the reaction of the molecule with concentrated NaOH followed by an acid (H⁺) treatment. The molecule in question is a ketone and an aldehyde, which suggests that a cross-aldol condensation reaction is taking place.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactant is a molecule with the structure CH₃-CH(CH₃)-CH₂-CHO, which contains both a ketone (the carbon chain with CH₃ groups) and an aldehyde (CHO group).

**Hint**: Look for functional groups present in the molecule to determine the type of reaction.

2. **Mechanism of Reaction**:
In the presence of concentrated NaOH, the base will deprotonate the aldehyde (CHO) group. This creates a nucleophile (the enolate ion) that can attack the carbonyl carbon of the ketone.

**Hint**: Remember that aldehydes are more reactive than ketones in nucleophilic addition reactions.

3. **Formation of Enolate Ion**:
The base (OH⁻) abstracts a hydrogen atom from the aldehyde, forming an enolate ion. The enolate ion is more nucleophilic and will attack the carbonyl carbon of the ketone.

**Hint**: The enolate ion is formed from the more acidic hydrogen adjacent to the carbonyl group.

4. **Nucleophilic Attack**:
The enolate ion attacks the carbonyl carbon of the ketone, leading to the formation of a β-hydroxy ketone. The structure will now include a new carbon-carbon bond between the aldehyde and the ketone.

**Hint**: Visualize the reaction mechanism to understand how the nucleophile interacts with the electrophile.

5. **Protonation**:
After the nucleophilic addition, the intermediate formed will be protonated by the addition of H⁺ (from the acid treatment), resulting in the formation of the final product.

**Hint**: Protonation usually occurs at the oxygen atom of the alkoxide formed during the reaction.

6. **Final Product**:
The final product of the reaction will be a β-hydroxy ketone. The structure can be represented as CH₃-CH(OH)-CH₂-CHO, which is a β-hydroxy aldehyde.

**Hint**: Check the connectivity of the atoms to ensure that the product matches the expected structure.

### Conclusion:
The product of the reaction is a β-hydroxy aldehyde, specifically CH₃-CH(OH)-CH₂-CHO.