In the following reaction final product is :
`C_(6)H_(5)MgBr +CO_(2) overset("Ether")to overset(H^(o+))to` find product

Options

A. Benzoic acid
B. Benzaldehyde
C. Benzamide
D. Benzene

Answer

To solve the problem, we need to analyze the reaction between phenylmagnesium bromide (C₆H₅MgBr) and carbon dioxide (CO₂) in the presence of ether and an acid (H⁺). Here’s a step-by-step breakdown of the reaction:

### Step 1: Identify the Reactants
The reactants in the reaction are:
- Phenylmagnesium bromide (C₆H₅MgBr)
- Carbon dioxide (CO₂)

### Step 2: Understand the Role of the Grignard Reagent
Phenylmagnesium bromide is a Grignard reagent. Grignard reagents are nucleophiles, meaning they can donate a pair of electrons to electrophiles. In this case, CO₂ acts as an electrophile.

### Step 3: Nucleophilic Attack
The nucleophilic carbon (C) of the phenyl group (C₆H₅) in C₆H₅MgBr will attack the electrophilic carbon of CO₂. This results in the formation of a carboxylate intermediate:
- The reaction can be represented as:
\[ C₆H₅MgBr + CO₂ \rightarrow C₆H₅C(=O)OMgBr \]

### Step 4: Protonation of the Carboxylate
After the formation of the carboxylate intermediate, the next step involves protonation. When the reaction mixture is treated with an acid (H⁺), the carboxylate ion will be protonated to form a carboxylic acid:
- The reaction can be represented as:
\[ C₆H₅C(=O)OMgBr + H⁺ \rightarrow C₆H₅C(=O)OH + MgBr^+ \]
- This product is benzoic acid (C₆H₅COOH).

### Step 5: Conclusion
The final product of the reaction is benzoic acid.

### Final Answer
The final product is **benzoic acid (C₆H₅COOH)**.

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