Which of the following will not yeild a cyclic compound on heating

Options

A.
B. `{:(CH_(2)-COOH),("|"),(CH_(2)-COOH):}`
C.
D.

Answer

To determine which of the given compounds will not yield a cyclic compound upon heating, we will analyze each option step by step.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We have four compounds to analyze. Let's denote them as:
- Option 1: CH2COOH (Formic Acid)
- Option 2: CH2CH2COOH (Butanoic Acid)
- Option 3: CH2CH2COOH (Butanoic Acid)
- Option 4: Thalymide (Cyclic compound with carboxylic groups)

2. **Analyze Option 1 (CH2COOH)**:
- When heated, both carboxylic groups are present on the same carbon.
- The reaction leads to the elimination of CO2, resulting in CH3COOH (Acetic Acid).
- Acetic Acid is a non-cyclic compound.

3. **Analyze Option 2 (CH2CH2COOH)**:
- Here, the carboxylic groups are on different carbons.
- Upon heating, water is eliminated (H and OH from the carboxylic groups).
- This results in a cyclic compound being formed.

4. **Analyze Option 3 (CH2CH2COOH)**:
- Similar to Option 2, the carboxylic groups are on different carbons.
- Heating leads to the elimination of water, forming a cyclic compound.

5. **Analyze Option 4 (Thalymide)**:
- This compound has a benzene ring with carboxylic groups.
- Upon heating, water is eliminated, leading to a cyclic compound formation.

6. **Conclusion**:
- From the analysis, Options 2, 3, and 4 yield cyclic compounds upon heating.
- However, Option 1 does not yield a cyclic compound; it yields acetic acid, which is linear.

### Final Answer:
**Option 1 (CH2COOH) will not yield a cyclic compound on heating.**

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