Aromatic carbonyl compound having molecular formula `C_(8)H_(8)O` react with `NH_(2)OH` how many oximes can be formed

Options

A. 8
B. 10
C. 12
D. 6

Answer

To solve the problem of how many oximes can be formed from an aromatic carbonyl compound with the molecular formula \( C_8H_8O \) when it reacts with hydroxylamine (\( NH_2OH \)), we can follow these steps:

### Step 1: Identify Possible Aromatic Carbonyl Compounds
We start by identifying the possible aromatic carbonyl compounds that can be formed with the given molecular formula \( C_8H_8O \). The two main types of aromatic carbonyl compounds are aldehydes and ketones.

1. **Aldehydes**:
- **Benzaldehyde**: \( C_6H_5CHO \)
- **Para-methylbenzaldehyde**: \( C_6H_4(CH_3)CHO \)
- **Meta-methylbenzaldehyde**: \( C_6H_4(CH_3)CHO \)
- **Ortho-methylbenzaldehyde**: \( C_6H_4(CH_3)CHO \)

2. **Ketones**:
- **Acetophenone**: \( C_6H_5C(O)CH_3 \)

From the above, we can identify a total of **five distinct aromatic carbonyl compounds** that fit the molecular formula \( C_8H_8O \).

### Step 2: Determine the Number of Isomers
Each of the identified carbonyl compounds can form oximes when reacted with hydroxylamine.

- Each carbonyl compound can have **two isomers** (due to the possibility of forming either of the two geometrical isomers of the oxime).

### Step 3: Calculate Total Oximes Formed
Now, we can calculate the total number of oximes formed by multiplying the number of carbonyl compounds by the number of isomers per compound:

\[ \text{Total Oximes} = \text{Number of Compounds} \times \text{Isomers per Compound} \]
\[ \text{Total Oximes} = 5 \times 2 = 10 \]

### Conclusion
Therefore, the total number of oximes that can be formed from the reaction of the aromatic carbonyl compound \( C_8H_8O \) with \( NH_2OH \) is **10**.

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