Number of possible intra molecular aldol condensation product on heating with NaOH
`H_(3)C-overset(O)overset(||)(C)-CH_(2)-CH_(2)-CH_(2)-overset(O)overset(||)(C)-H`

Options

A. 1
B. 2
C. 3
D. 4

Answer

To determine the number of possible intramolecular aldol condensation products from the given compound, we can follow these steps:

### Step 1: Identify the Structure
The compound given is:
`H3C-C(=O)-C-CH2-CH2-CH2-C(=O)-H`

This compound has two carbonyl groups (aldehydes) and a long carbon chain in between.

### Step 2: Recognize Aldol Condensation
Aldol condensation involves the formation of an enolate ion from one carbonyl compound, which then attacks another carbonyl group to form a β-hydroxy carbonyl compound. This can happen intramolecularly if the structure allows for it.

### Step 3: Identify Possible Anions
We need to find the different positions from which enolate ions can be formed. In this case, we can form anions from the following positions:

1. **From the first carbonyl (C=O) at the left end**: This will lead to an enolate that can attack the second carbonyl.
2. **From the second carbonyl (C=O) at the right end**: This will lead to an enolate that can attack the first carbonyl.
3. **From the carbon between the two carbonyls**: This carbon can also form an enolate and attack either of the carbonyls.

### Step 4: Count Unique Anions
Now, we count the unique anions formed:

- **Anion 1**: Formed from the first carbonyl (left).
- **Anion 2**: Formed from the second carbonyl (right).
- **Anion 3**: Formed from the carbon between the two carbonyls.

### Step 5: Determine the Number of Products
Since the molecule is unsymmetrical, each of these anions can lead to a different aldol product. Therefore, we have a total of 3 unique anions leading to 3 unique products.

### Conclusion
The number of possible intramolecular aldol condensation products is **3**.

### Final Answer
**The answer is 3.**

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