`A(C_(6)H_(12))overset(HCl)to underset((C_(6)H_(13)C))(B+C)`
`B overset(alc KOH)toD` (isomer of A)
`D overset("ozonolysis")toE` (it gives negative test with Fehling solution but responds to iodoform test).
`A overset("ozolysis")toF+G` (Both give positive Tollen's but do not give iodoform test)
`F+G overset("conc. NaOH")to` HCOONa +a primary alcohol
Identify to A to G

Answer

To identify the structures of compounds A to G based on the given reactions, we can follow these steps:

### Step 1: Identify Compound A
- **Given:** A (C₆H₁₂) reacts with HCl to give B + C.
- **Analysis:** Since A is a hydrocarbon with the formula C₆H₁₂, it is likely an alkene. The reaction with HCl suggests that it undergoes electrophilic addition, resulting in two products (B and C) that are both C₆H₁₃Cl.
- **Structure of A:** A can be identified as 3-hexene or 2-hexene (since both can yield different products upon reaction with HCl).

### Step 2: Identify Compounds B and C
- **Given:** B is formed from A and reacts with alcoholic KOH to give D (isomer of A).
- **Analysis:** B must be a chloroalkane (C₆H₁₃Cl). The elimination reaction with alcoholic KOH suggests that B is likely 3-chlorohexane, leading to the formation of D through dehydrohalogenation.
- **Structure of B:** B = 3-chlorohexane.
- **Structure of C:** C = 2-chlorohexane (the less stable isomer).

### Step 3: Identify Compound D
- **Given:** D is an isomer of A (C₆H₁₂).
- **Analysis:** Since D is formed from B through elimination, it would be 3-hexene (the double bond is formed by removing HCl).
- **Structure of D:** D = 3-hexene.

### Step 4: Identify Compound E
- **Given:** D undergoes ozonolysis to give E, which gives a negative test with Fehling solution but responds to the iodoform test.
- **Analysis:** Ozonolysis of D (3-hexene) will yield two molecules of a ketone. Since E gives a positive iodoform test, it must be a methyl ketone.
- **Structure of E:** E = 3-pentanone.

### Step 5: Identify Compounds F and G
- **Given:** A undergoes ozonolysis to give F + G, both of which give positive Tollen's test but do not give the iodoform test.
- **Analysis:** The ozonolysis of A (3-hexene) will yield two aldehydes. Since they give a positive Tollen's test, they are likely to be straight-chain aldehydes.
- **Structure of F:** F = butanal (C₄H₈O).
- **Structure of G:** G = propanal (C₃H₆O).

### Step 6: Final Identification
- **A:** 3-hexene (C₆H₁₂)
- **B:** 3-chlorohexane (C₆H₁₃Cl)
- **C:** 2-chlorohexane (C₆H₁₃Cl)
- **D:** 3-hexene (C₆H₁₂)
- **E:** 3-pentanone (C₅H₁₀O)
- **F:** Butanal (C₄H₈O)
- **G:** Propanal (C₃H₆O)