In the following reaction sequence, the compound J is an
interemediate
`Iunderset(CH_(3)COONa)overset((CH_(3)CO)_(2)O)(to)J underset({:((ii)SOCl_(2)),((iii)"anhyd".AlCl_(3)):})overset((i)H_(2),Pd//C)(to)K`
`J(C_(9)H_(8)O_(2))` gives effervsecence on the treament with` NaHCHO_(3)`
and positive Baeyr's test.
The compound I , is

Options

A.
B.
C.
D.

Answer

To solve the question step by step, we need to analyze the given reaction sequence and identify the compound I based on the information provided.

### Step 1: Understanding the Reaction Sequence
The question states that compound J is formed from compound I through a reaction with sodium acetate (CH₃COONa) and acetic anhydride ((CH₃CO)₂O). This suggests that a condensation reaction takes place, likely a Claisen condensation or a similar reaction.

**Hint:** Look for reactions involving carbonyl compounds and consider the role of sodium acetate and acetic anhydride.

### Step 2: Identifying Compound J
The compound J is given as C₉H₈O₂. The information about J giving effervescence with NaHCO₃ indicates that it is likely a carboxylic acid, as carboxylic acids react with bicarbonates to produce carbon dioxide gas. The positive Baeyer's test indicates the presence of a double bond, specifically a carbon-carbon double bond.

**Hint:** Focus on the molecular formula C₉H₈O₂ and consider the functional groups that could be present.

### Step 3: Deducing the Structure of J
Given that J is a carboxylic acid with a double bond, it is likely to be cinnamic acid (C₉H₈O₂), which has the structure of a phenyl group attached to a vinyl group (C=C) and a carboxylic acid (–COOH).

**Hint:** Sketch the structure of cinnamic acid to visualize its functional groups.

### Step 4: Identifying Compound I
Since J is formed from I through a reaction with sodium acetate and acetic anhydride, and considering that the reaction is likely a condensation reaction, compound I must be benzaldehyde (C₇H₆O). Benzaldehyde can react with sodium acetate in a condensation reaction to form cinnamic acid.

**Hint:** Recall the structure of benzaldehyde and consider how it can lead to the formation of a compound like cinnamic acid.

### Step 5: Conclusion
Thus, the compound I is benzaldehyde (C₇H₆O).

### Final Answer
The compound I is benzaldehyde (C₇H₆O).

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