`PhCHO +(CH_(3)CO)_(2)O overset((1)CH_(3)COONa)underset((2)"hydrolysis", Delta)toA overset(HBr)toB B`
The product B is

Options

A. `PhCH=CHCH_(2)Br`
B. `Phunderset(Br)underset(|)(C)H-CH_(2)-COOH`
C. `PhCH_(2)CH(Br)COOH`
D. `PhCH=CH-COBr`

Explanation

To solve the problem step by step, we need to analyze the reactions taking place between the given compounds.

### Step 1: Identify the Reactants
The reactants in the reaction are:
- **PhCHO**: This is benzaldehyde (or benzyldehyde).
- **(CH₃CO)₂O**: This is acetic anhydride.

### Step 2: Understand the Reaction Conditions
The reaction is facilitated by:
- **CH₃COONa**: This is sodium acetate, which acts as a catalyst.
- **Hydrolysis**: This indicates that water will be involved in the reaction, leading to the formation of a product.

### Step 3: Perform the Reaction (Perkin Condensation)
The reaction between benzaldehyde and acetic anhydride in the presence of sodium acetate is an example of the **Perkin condensation**. This reaction leads to the formation of a compound known as **cinnamic acid**.

The structure of cinnamic acid can be represented as:
- **C6H5-CH=CH-COOH**

### Step 4: Identify Product A
After the first step, the product A formed is **cinnamic acid** (C6H5-CH=CH-COOH).

### Step 5: Second Reaction with HBr
In the second part of the reaction, cinnamic acid reacts with **HBr**. This reaction involves the addition of HBr across the double bond of cinnamic acid, following Markovnikov's rule.

### Step 6: Form Product B
The addition of HBr to cinnamic acid results in the formation of **3-bromo-3-phenylpropanoic acid**. The structure can be represented as:
- **C6H5-CHBr-CH2-COOH**

### Step 7: Identify Product B
Thus, the final product B is **3-bromo-3-phenylpropanoic acid**.

### Conclusion
The final answer to the question is that the product B is **3-bromo-3-phenylpropanoic acid**.

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