Give the reaction of boric Acid with caustic Soda

Explanation

To solve the question about the reaction of boric acid with caustic soda, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are boric acid (H₃BO₃) and caustic soda (NaOH).

### Step 2: Write the Chemical Equation
When boric acid reacts with caustic soda, the products formed are sodium meta borate (NaBO₂) and water (H₂O). The unbalanced chemical equation can be written as:
\[ \text{H}_3\text{BO}_3 + \text{NaOH} \rightarrow \text{NaBO}_2 + \text{H}_2\text{O} \]

### Step 3: Balance the Chemical Equation
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides. The balanced equation is:
\[ \text{H}_3\text{BO}_3 + 2\text{NaOH} \rightarrow \text{NaBO}_2 + 2\text{H}_2\text{O} \]

### Step 4: Write the Final Balanced Reaction
The final balanced reaction of boric acid with caustic soda is:
\[ \text{H}_3\text{BO}_3 + 2\text{NaOH} \rightarrow \text{NaBO}_2 + 2\text{H}_2\text{O} \]

### Summary of the Reaction
- **Reactants**: Boric acid (H₃BO₃) and caustic soda (NaOH)
- **Products**: Sodium meta borate (NaBO₂) and water (H₂O)