Identify final product In the following reaction `CH_(3)-underset(OH)underset(|)(C)H-COOH overset(Delta)to` product

Options

A.
B. `CH_(2)-=CH-COOH`
C. `CH_(3)-underset(O)underset(||)(C)-COOH`
D. `CH_(3)-CH_(2)-OH`

Explanation

To identify the final product of the given reaction, we will analyze the reactant and the conditions under which the reaction occurs. The reactant is a compound containing both a carboxylic acid group and a hydroxyl group. Let's break down the steps:

### Step 1: Identify the Reactant
The reactant is given as CH₃-CH(OH)-C(=O)OH, which is a carboxylic acid with a hydroxyl group.

### Step 2: Understand the Reaction Conditions
The reaction is carried out under heating (Δ), which indicates that the reaction is likely to involve dehydration (loss of water).

### Step 3: Dehydration Reaction
When a carboxylic acid reacts with a hydroxyl group under heat, a dehydration reaction occurs. In this case, the hydroxyl group (–OH) from the carboxylic acid and a hydrogen atom (H) from the hydroxyl group will be removed, leading to the formation of water (H₂O).

### Step 4: Formation of the Final Product
The remaining parts of the molecule will then combine to form a cyclic compound. The dehydration will result in the formation of a cyclic ester (also known as a lactone). The structure will involve a carbonyl group (C=O) and an ether linkage (–O–) in a ring.

### Step 5: Drawing the Final Product
The final product can be represented as follows:
- The cyclic structure will have an oxygen atom in the ring and will connect two carbon atoms that were originally part of the carboxylic acid and hydroxyl group.
- The final product will be a cyclic compound with the structure:

```
O
/ \
C C
// \\
C C
```

### Conclusion
The final product of the reaction is a cyclic compound (lactone) formed by the dehydration of the original reactant.

### Final Product
The final product is a cyclic ester (lactone) formed from the dehydration of the reactant.

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