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Graph between log""x/m and log P is a s...

Graph between `log""x/m` and log P is a straight line inclined at an angle `Cl_4`When pressure is 0.5 atm and log k=0.699, the amount of solute adsorbed per g of adsorbent will be:

A

`1`

B

`1.5`

C

`0.25`

D

`2.5`

Text Solution

Verified by Experts

The correct Answer is:
A
`"log" (x)/(M) = log K + (1)/(n) log P`
`(1)/(n) = tan 45^(@) " " "In " k = 0.69`
`n = 1 " " k = 2`
`(x)/(m) = 2 xx (0.5)^(1)`
x = 1
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