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A particle is revolving in a circular pa...

A particle is revolving in a circular path as shown in figure in the horizontal plane such that the angular velocity of the particle about the point O is constant and is equal to `1 rad//s`. Distance of the particle from O is given by`R=R_(0)-betat` where `R_(0)`and `beta` are constant. The speed of the particle as a function of time is:

A

`sqrt(beta^(2)+1)`

B

`(R_(0)+beta t)`

C

`beta`

D

`sqrt(beta^(2)+(R_(0)+beta t)^(2))`

Text Solution

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The correct Answer is:
D
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