How many moles of electrons are required for reduction of 2 moles of`Zn^(2+)` to Zn ?

Answer

To determine how many moles of electrons are required for the reduction of 2 moles of \( \text{Zn}^{2+} \) to Zn, we can follow these steps:

### Step 1: Understand the Reduction Process
Reduction is the gain of electrons. In this case, \( \text{Zn}^{2+} \) is being reduced to Zn. The half-reaction for the reduction of zinc ions can be written as:
\[ \text{Zn}^{2+} + 2e^- \rightarrow \text{Zn} \]

### Step 2: Determine the Number of Electrons Needed for One Mole
From the half-reaction, we see that 1 mole of \( \text{Zn}^{2+} \) requires 2 moles of electrons (2e^-) to be reduced to 1 mole of Zn.

### Step 3: Calculate for 2 Moles of \( \text{Zn}^{2+} \)
Since we have 2 moles of \( \text{Zn}^{2+} \), we can calculate the total moles of electrons required:
\[ \text{For 2 moles of } \text{Zn}^{2+} = 2 \text{ moles of } \text{Zn}^{2+} \times 2 \text{ moles of electrons per mole of } \text{Zn}^{2+} = 4 \text{ moles of electrons} \]

### Conclusion
Thus, the total number of moles of electrons required for the reduction of 2 moles of \( \text{Zn}^{2+} \) to Zn is 4 moles.

### Final Answer
**4 moles of electrons are required.**

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