For the reaction `2NOBr to 2NO_2 + Br_2,` the rate law is rate =` k[NOBr]^2`. If the rate of a reaction is `6.5xx10^(-6) molL^(-1)s^(-1)`, when the concentration of NOBr is `2xx10^(-3) molL^(-1)`.What would be the rate constant of the reaction?

The rate of a second order reaction is 6 xx 10^(-5) mol L^(-1) s^(-1) , when the initial concentration is 0.2 mol L^(-1) . The rate constant is………………… .

The rate first order reaction is 2.4 xx 10^(-3) mol L^(-1) s^(-1) , when the initial concentration is 0.2 mol L^(-1) . The rate constant is…………. .

The rate of a reaction increases four-fold when the concentration of reactant is increased 16 times. If the rate of reaction is 4 xx 10^(-6) mol L^(-1) s^(-1) when the concentration of the reactant is 4 xx 10^(-4) mol L^(-1) . The rate constant of the reaction will be

The specific rate of a reaction is 6.2 xx 10^(-3) molL^(-1)s^(-1) . What is the order of the reactions?

The rate constant of a reaction is 2.5xx10^(-2) "minutes"^(-1) The order of the reaction is