Home
Class 12
PHYSICS
Show that for diatomic gas the ratio of ...

Show that for diatomic gas the ratio of the two specific heats is 7:5.

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • QUESTION BANK 2021

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Kinetic Theory of gases and Radiation ( Short Answer II (SA2) ( 3 MARKS Each ) )|10 Videos

  • QUESTION BANK 2021

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Kinetic Theory of gases and Radiation (Long Answer ( LA) ( 4 marks Each) )|3 Videos

  • QUESTION BANK 2021

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Kinetic Theory of gases and Radiation (Very Short Answer (VSA) ( 1 MARK Each ) )|7 Videos

  • MULTIPLE CHOICE QUESTIONS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Communication Systems|6 Videos

  • SHORT ANSWER QUESTIONS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Assignments|3 Videos

Similar Questions

Explore conceptually related problems

Show that for monoatomic gas the ratio of the two specific heats is 5:3.

If f denotes the degree of freedom of a gas, the ratio of two specific heats (C_(P))/(C_(V)) is given by

The molar specific heat of a gas at constant volume is 12307.69 J kg^(-1) K^(-1) . If the ratio of the two specific heats is 1.65, calculate the difference between the two molar specific heats of gas.

One mole of a monatomic gas is mixed with 3 moles of a diatomic gas. What is the molar specific heat of the mixture at constant volume?

For a gas the differce between the two specific heat is 4150 J//kg K . What is the specific heat at constant volume of gas if the ratio of sepcific heat is 1.4

Supposing the distance between the atoms of a diatomic gas to be constant, its specific heat at constant volume per mole (gram mole) is

If 2 moles of diatomic gas and 1 mole of monatomic gas are mixed, then the ratio of specific heats for the mixture is