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1000 calories of radiant heat is inciden...

1000 calories of radiant heat is incident on a body. If the body absorbs 400 calories of heat, find the coefficient of emission of the body.

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To solve the problem of finding the coefficient of emission of a body that absorbs a certain amount of radiant heat, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Total radiant heat incident on the body (Q_incident) = 1000 calories - Heat absorbed by the body (Q_absorbed) = 400 calories 2. **Understanding the Coefficient of Emission:** - The coefficient of emission (e) is defined as the ratio of the heat absorbed by the body to the heat incident on it. - Mathematically, this can be expressed as: \[ e = \frac{Q_{\text{absorbed}}}{Q_{\text{incident}}} \] 3. **Substituting the Values:** - Now, substitute the given values into the formula: \[ e = \frac{400 \text{ calories}}{1000 \text{ calories}} \] 4. **Calculating the Coefficient:** - Simplifying the fraction: \[ e = \frac{400}{1000} = 0.4 \] 5. **Conclusion:** - The coefficient of emission of the body is 0.4. Since it is a coefficient, it is dimensionless and does not have any units. ### Final Answer: The coefficient of emission of the body is **0.4**.
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