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Determine the molecular kinetic energy p...

Determine the molecular kinetic energy per gram of nitrogen molecules at `227 ""^(@)C, R = 8.310 J "mol"e^(-1) K^(-1)`,No = `6.03 xx 10^(26)` moleculesKmol`e^(- 1)`. Molecular weight of nitrogen = 28.

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The correct Answer is:
K.E. per kilogram = `0.225 xx 10^(2)` J/kg
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Determine the molecular kinetic energy per molecule of nitrogen molecules at 227 ""^(@)C, R = 8.310 J "mol"e^(-1) K^(-1) ,No = 6.03 xx 10^(26) moleculesKmol e^(- 1) . Molecular weight of nitrogen = 28.

Determine the molecular kinetic energy per mole of nitrogen molecules at 227 ""^(@)C, R = 8.310 J "mol"e^(-1) K^(-1) ,No = 6.03 xx 10^(26) moleculesKmol e^(- 1) . Molecular weight of nitrogen = 28.

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