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Light of wavelength 5000 A.falls on a pl...

Light of wavelength 5000 A.falls on a plane reflecting surface. The frequency of reflected light is…

A

`6 xx 10^(14)`Hz

B

` 5 xx 10^(14)`Hz

C

`2xx10^(14)Hz`

D

`1.666xx10^(14)Hz`

Text Solution

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The correct Answer is:
To find the frequency of the reflected light when light of wavelength 5000 Angstroms falls on a plane reflecting surface, we can follow these steps: ### Step 1: Understand the relationship between speed, frequency, and wavelength The speed of light (v) is related to its frequency (ν) and wavelength (λ) by the equation: \[ v = ν \cdot λ \] Where: - \( v \) is the speed of light (approximately \( 3 \times 10^8 \) m/s), - \( ν \) is the frequency in hertz (Hz), - \( λ \) is the wavelength in meters (m). ### Step 2: Convert the wavelength from Angstroms to meters The given wavelength is 5000 Angstroms. To convert Angstroms to meters, we use the conversion factor: \[ 1 \, \text{Angstrom} = 10^{-10} \, \text{meters} \] Thus, \[ λ = 5000 \, \text{Angstroms} = 5000 \times 10^{-10} \, \text{meters} = 5 \times 10^{-7} \, \text{meters} \] ### Step 3: Substitute the values into the frequency formula Now, we can rearrange the equation \( v = ν \cdot λ \) to solve for frequency: \[ ν = \frac{v}{λ} \] Substituting the values: \[ ν = \frac{3 \times 10^8 \, \text{m/s}}{5 \times 10^{-7} \, \text{m}} \] ### Step 4: Calculate the frequency Calculating the frequency: \[ ν = \frac{3 \times 10^8}{5 \times 10^{-7}} = 3 \times 10^8 \times \frac{1}{5} \times 10^7 = \frac{3}{5} \times 10^{15} \] \[ ν = 0.6 \times 10^{15} \, \text{Hz} = 6 \times 10^{14} \, \text{Hz} \] ### Conclusion The frequency of the reflected light is: \[ ν = 6 \times 10^{14} \, \text{Hz} \] ---
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