What should be the slit width to obtain pronounced diffraction with a single slit illuminated by light of wavelength `lamda`?

The diffraction fringes obtained by a single slit are of

Angular width of central maximum in diffraction at a single slit is……………. .

A narrow slit is illuminated by a parallel beam of monochromatic light of wavelength lambda_(0) equals to 6000 A^(0) and the angular width of the central maxima in the resulting diffraction pattern is measured.When the slit is next illuminated by light of wavelength lambda ,the angular width decreases to half.Calculate the value of the wavelength lambda .

Angular width of central maxima in the Fraunhofer diffraction pattern of a slit is measured. The slit is illuminated by light of wavelength 6000Å . When the slit is illuminated by light of another wavelength, the angular width decreases by 30%. The wavelength of this light will be

In a single slit diffraction pattern the angular width of a central maxima is 30^(@) . When the slit is illuminated by light of wavelength 6000Å . Then width of the slit will be approximately given as :

Angular width of central maximum in the Fraunhoffer diffraction pattern of a slit is measured. The slit is illuminated by light of wavelength 6000Å . When the slit is illuminated by light of another wavelength, the angular width decreases by 30% . Calculate the wavelength of this light. The same decrease in the angular width of central maximum is obtained when the original apparatus is immersed in a liquid. Find the refractive index of the liquid.

The condition for observing Fraunhofer diffraction from a single slit is that the light wavefront incident on the slit should be

Angular width of central maxima is pi//2 , when a slit of width 'a' is illuminated by a light of wavelength 7000 Å then a =