Home
Class 12
PHYSICS
Light of wavelength lambda=5000Å falls n...

Light of wavelength `lambda=5000Å` falls normally on a narrow slit. A screen is placed at a distance of `1m` from the slit and perpendicular to the direction of light. The first minima of the diffraction pattern is situated at `5mm` from the centre of central maximum. The width of the slit is

Text Solution

Verified by Experts

The correct Answer is:
5000 A.U.
Promotional Banner

Topper's Solved these Questions

  • QUESTION BANK 2021

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise WAVE OPTICS (Long Answer ( LA) ( 4 marks Each) )|1 Videos

  • QUESTION BANK 2021

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Electrostatics (MCQ’S (1 Mark Each) )|7 Videos

  • QUESTION BANK 2021

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise WAVE OPTICS (Short Answer I (SA1) ( 2 MARKS Each ) )|8 Videos

  • MULTIPLE CHOICE QUESTIONS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Communication Systems|6 Videos

  • SHORT ANSWER QUESTIONS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Assignments|3 Videos

Similar Questions

Explore conceptually related problems

A screen is placed at a distance of 1m from a narrow slit. Light of wavelength 0.5 micron is fallilng normally on the slit. If the first minima of the diffraction pattern is situated at 5 m m from the central maximum, find the width of the slit.

The first diffraction minima in a single slit diffraction pattern is at theta=30^(@) , for light of wavelength=5000 Å. The width of the slit is

Light of wavelength 6000 A^(@) is incident on a single slit. The first minimum of the diffraction pattern is obtained at 4 mm from the centre. The screen is at a distance of 2 m from the silt. The slit width will be

Visible light of wavelength 500 nm falls normally on a single slit and produces a diffraction pattern. It is found that the diffraction pattern is on a screen 1 m away from slit. If the first minimum is produced at a distance of 2.5 mm from the centre of screen, then the width of the slit is

Light d of wavelength 5000Å is incident normally on a slite. The first minimum of the distance of 5 mm from the central maximum on a screen placed at a distance of 2 m from the slit. The width of slit is

Light of wavelength 6000Å is incident on a slit of width 0.30 mm. The screen is placed 2 m from the slit. Find (a) the position of the first dark fringe and (b). The width of the central bright fringe.

The first diffraction minima due to a single slit diffraction is at theta=30^(@) for a light of wavelength 5000Å The width of the slit is

The first diffraction minima due to a single slit diffraction is at q = 30^(@) for a light of wavelength 5000 Å. The width of the slit is-

light of wavelength 600 nm is incident on a single slit. The first minimum of athe diffraction pattern is obtained at a distance of 4 m m from the centre. The distance between the screen and the slit is 2 m . What is the width of the slit ?

A screen is placed at 50cm from a single slit, which is illuminated with 600nm light. If separation between the first and third minima in the diffraction pattern is 3.0mm , then width of the slit is: