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The maximum safe voltage that can be mea...

The maximum safe voltage that can be measured using a galvanometer of resistance G is `V_(m)` . Find the resistance to be connected in series with the galvanometer so that it becomes a voltmeter of range `nV_(m)`.

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To solve the problem of finding the resistance to be connected in series with a galvanometer to convert it into a voltmeter of range \( nV_m \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: - We have a galvanometer with a maximum safe voltage \( V_m \) and resistance \( G \). - We want to measure a higher voltage, specifically \( nV_m \), using the galvanometer. 2. **Voltage Drop Across the Galvanometer**: - The galvanometer can safely measure up to \( V_m \). When we want to measure \( nV_m \), the additional voltage that needs to be dropped across the series resistance \( R_s \) is: \[ V_{drop} = nV_m - V_m = (n - 1)V_m \] 3. **Current Through the Circuit**: - The current \( I_G \) flowing through the galvanometer when measuring the maximum voltage \( V_m \) can be expressed as: \[ I_G = \frac{V_m}{G} \] - This is because the current through the galvanometer is the voltage across it divided by its resistance. 4. **Total Voltage in the Circuit**: - When the galvanometer and the series resistance \( R_s \) are connected, the total voltage across the circuit is \( nV_m \). The relationship can be expressed as: \[ I_G = \frac{nV_m}{R_{eq}} \] - Here, \( R_{eq} \) is the equivalent resistance of the circuit, which is the sum of the galvanometer resistance and the series resistance: \[ R_{eq} = R_s + G \] 5. **Setting Up the Equation**: - Since both expressions for \( I_G \) are equal, we can set them equal to each other: \[ \frac{V_m}{G} = \frac{nV_m}{R_s + G} \] 6. **Cross-Multiplying**: - Cross-multiplying gives: \[ V_m(R_s + G) = nV_m \cdot G \] 7. **Simplifying the Equation**: - Dividing both sides by \( V_m \) (assuming \( V_m \neq 0 \)): \[ R_s + G = nG \] - Rearranging gives: \[ R_s = nG - G = (n - 1)G \] 8. **Final Result**: - Therefore, the resistance \( R_s \) that needs to be connected in series with the galvanometer is: \[ R_s = (n - 1)G \] ### Summary: To convert a galvanometer with resistance \( G \) into a voltmeter capable of measuring up to \( nV_m \), connect a resistance of \( (n-1)G \) in series with it.
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