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Calculate the gyro magnetic ratio of ele...

Calculate the gyro magnetic ratio of electron
(given 1.6`xx10^(-19)` C, `m_r=9.1xx10^(-3)` kg )

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To calculate the gyromagnetic ratio of an electron, we can use the formula: \[ \text{Gyromagnetic Ratio} (\gamma) = \frac{E}{2m} \] where: - \(E\) is the charge of the electron, - \(m\) is the mass of the electron. Given: - Charge of electron, \(E = 1.6 \times 10^{-19} \, \text{C}\) - Mass of electron, \(m = 9.1 \times 10^{-31} \, \text{kg}\) Now, let's substitute the values into the formula: \[ \gamma = \frac{1.6 \times 10^{-19}}{2 \times 9.1 \times 10^{-31}} \] Step 1: Calculate the denominator. \[ 2m = 2 \times 9.1 \times 10^{-31} = 1.82 \times 10^{-30} \, \text{kg} \] Step 2: Substitute the denominator back into the gyromagnetic ratio formula. \[ \gamma = \frac{1.6 \times 10^{-19}}{1.82 \times 10^{-30}} \] Step 3: Perform the division. \[ \gamma = \frac{1.6}{1.82} \times 10^{(-19 + 30)} = \frac{1.6}{1.82} \times 10^{11} \] Step 4: Calculate the numerical value. \[ \frac{1.6}{1.82} \approx 0.879 \] Thus, \[ \gamma \approx 0.879 \times 10^{11} \approx 8.79 \times 10^{10} \, \text{C/kg} \] So, the gyromagnetic ratio of the electron is approximately: \[ \gamma \approx 8.79 \times 10^{10} \, \text{C/kg} \]
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An electron in an atom is revolving round the nucleus in a circular orbit of radius 5.3xx10^(-11) m, with a speed of 2xx10^(6)ms^(-1) . Find resultant orbital magnetic moment and angular momentum of electron. (e = 1.6 xx 10^(-19) C , m = 9.1 xx 10 kg )

If de Broglie wavelength of an electron is 0.5467 Å, find the kinetic energy of electron in eV. Given h=6.6xx10^(-34) Js , e= 1.6xx10^(-19) C, m_e=9.11xx10^(-31) kg.

Knowledge Check

  • A cathode ray beam is bent into an arc of a circle of radius 0.02m by a field of magnetic induction 4.55 milli tesla. The velocity of electron is (given e=1.6xx10^(-19) c and m=1.9xx10^(-31)kg)

    A
    `2xx10^(7) m//s`
    B
    `3xx10^(7)m//s`
    C
    `1.6xx10^(7)m//s`
    D
    `3.2xx10^(7)m//s`
  • An electron is moving in a cyclotron at a speed of 3.2 xx 10^(7) m s^(-1) in a magnetic field of 5 xx 10^(-4) T perpendicular to it. What is the frequency of this electron? (q=1.6xx10^(-19)C, m_(c)=9.1xx10^(-31)kg)

    A
    `1.4xx10^(5)Hz`
    B
    `1.4xx10^(7)Hz`
    C
    `1.4xx10^(6)Hz`
    D
    `1.4xx10^(9)Hz`
  • An electron is accelerated under a potential difference of 64 V, the de-Brogile wavelength associated with electron is [e = -1.6 xx 10^(-19) C, m_(e) = 9.1 xx 10^(-31)kg, h = 6.623 xx 10^(-34) Js]

    A
    `1. 53 Å`
    B
    `2. 53 Å`
    C
    `3. 35 Å`
    D
    `4. 54 Å`
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