Two pure inductors each of self inductance L are connected in series, the net inductance is

Options

A. 2L
B. L
C. L/2
D. L/4

Answer

To find the net inductance of two pure inductors connected in series, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Self Inductance of Each Inductor**:
Let the self inductance of each inductor be denoted as \( L \). Since there are two inductors, we have:
- Inductor 1: \( L_1 = L \)
- Inductor 2: \( L_2 = L \)

2. **Use the Formula for Inductors in Series**:
When inductors are connected in series, the total or net inductance \( L_{net} \) is simply the sum of the individual inductances. The formula is:
\[ L_{net} = L_1 + L_2 \]

3. **Substitute the Values**:
Substitute the values of \( L_1 \) and \( L_2 \) into the formula:
\[ L_{net} = L + L \]

4. **Simplify the Expression**:
Combine the terms:
\[ L_{net} = 2L \]

5. **Conclusion**:
Therefore, the net inductance of the two inductors connected in series is:
\[ L_{net} = 2L \]

### Final Answer:
The net inductance is \( 2L \).