An aircraft of wing span of 50 m flies horizontally in earth's magnetic field of 6 x `10^(-5) at a speed of 400 m/s. Calculate the emf generated between the tips of the wings of the aircraft.

Answer

To calculate the electromotive force (emf) generated between the tips of the wings of the aircraft, we can use the formula for emf generated in a conductor moving through a magnetic field:

\[ \text{emf} = B \cdot L \cdot v \]

where:
- \( B \) is the magnetic field strength (in tesla),
- \( L \) is the length of the conductor (in meters), which in this case is the wingspan of the aircraft,
- \( v \) is the velocity of the conductor (in meters per second).

### Step-by-Step Solution:

1. **Identify the values:**
- Wingspan \( L = 50 \, \text{m} \)
- Magnetic field \( B = 6 \times 10^{-5} \, \text{T} \)
- Speed \( v = 400 \, \text{m/s} \)

2. **Substitute the values into the formula:**
\[ \text{emf} = (6 \times 10^{-5} \, \text{T}) \cdot (50 \, \text{m}) \cdot (400 \, \text{m/s}) \]

3. **Calculate the product:**
- First, calculate \( 6 \times 10^{-5} \times 50 \):
\[ 6 \times 10^{-5} \times 50 = 3 \times 10^{-3} \, \text{T m} \]
- Now, multiply this result by the speed \( 400 \, \text{m/s} \):
\[ 3 \times 10^{-3} \, \text{T m} \times 400 \, \text{m/s} = 1200 \times 10^{-3} \, \text{V} = 1.2 \, \text{V} \]

4. **Final Result:**
The emf generated between the tips of the wings of the aircraft is:
\[ \text{emf} = 1.2 \, \text{V} \]