In a transistor amplifier, IC = 5.5 mA , IE = 5.6 mA. The current amplification facto β is…

Options

A. 45
B. 50
C. 55
D. 60

Answer

To find the current amplification factor (β) in a transistor amplifier, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values:**
- Collector current (IC) = 5.5 mA
- Emitter current (IE) = 5.6 mA

2. **Understand the relationship between the currents:**
- The relationship between the emitter current (IE), collector current (IC), and base current (IB) is given by the equation:
\[ IE = IB + IC \]

3. **Rearrange the equation to find IB:**
- We can rearrange the equation to solve for base current (IB):
\[ IB = IE - IC \]

4. **Substitute the known values:**
- Substitute the values of IE and IC into the equation:
\[ IB = 5.6 \, \text{mA} - 5.5 \, \text{mA} = 0.1 \, \text{mA} \]

5. **Calculate the current amplification factor (β):**
- The current amplification factor (β) is defined as the ratio of the collector current (IC) to the base current (IB):
\[ β = \frac{IC}{IB} \]
- Substitute the values of IC and IB:
\[ β = \frac{5.5 \, \text{mA}}{0.1 \, \text{mA}} = 55 \]

### Final Answer:
- The current amplification factor (β) is **55**.

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