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If x= 2at , y= 2a , where t is parameter...

If x= 2at , y= 2a , where t is parameter, then `(dy)/(dx) = 1/t`. (True/False)

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To determine whether the statement \((dy)/(dx) = 1/t\) is true or false given \(x = 2at\) and \(y = 2a\), we will follow these steps: ### Step 1: Write down the equations We have: \[ x = 2at \] \[ y = 2a \] ### Step 2: Differentiate both equations with respect to \(t\) Differentiate \(x\) with respect to \(t\): \[ \frac{dx}{dt} = \frac{d}{dt}(2at) = 2a \] Now differentiate \(y\) with respect to \(t\): \[ \frac{dy}{dt} = \frac{d}{dt}(2a) = 0 \] (since \(2a\) is a constant). ### Step 3: Use the chain rule to find \(\frac{dy}{dx}\) Using the chain rule, we have: \[ \frac{dy}{dx} = \frac{dy}{dt} \cdot \frac{dt}{dx} \] ### Step 4: Substitute the values we found We already found: \[ \frac{dy}{dt} = 0 \] And we need to find \(\frac{dt}{dx}\). We can find \(\frac{dt}{dx}\) by taking the reciprocal of \(\frac{dx}{dt}\): \[ \frac{dt}{dx} = \frac{1}{\frac{dx}{dt}} = \frac{1}{2a} \] Now substituting into the equation for \(\frac{dy}{dx}\): \[ \frac{dy}{dx} = 0 \cdot \frac{1}{2a} = 0 \] ### Step 5: Compare with the given statement The statement claims that \(\frac{dy}{dx} = \frac{1}{t}\). We found that: \[ \frac{dy}{dx} = 0 \] Since \(0 \neq \frac{1}{t}\) (for any \(t \neq 0\)), the statement is **False**. ### Final Answer: The statement \((dy)/(dx) = 1/t\) is **False**. ---
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