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Mean of x= 25 Mean of y =20 sigmax =...

Mean of x= 25
Mean of y =20
`sigma_x = 4`
` sigma_y=3`
` r = 0.5`
`b_(yx) = square`
`b_(xy)= square`
When x = 10
`y-square=square(10 - square)`
`:. y = square`

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To solve the problem step by step, we will follow the instructions provided in the video transcript. ### Step 1: Calculate the regression coefficient \( b_{yx} \) The formula for the regression coefficient \( b_{yx} \) is given by: \[ b_{yx} = r \cdot \frac{\sigma_y}{\sigma_x} \] Where: - \( r = 0.5 \) - \( \sigma_y = 3 \) - \( \sigma_x = 4 \) Substituting the values: \[ b_{yx} = 0.5 \cdot \frac{3}{4} = \frac{5}{10} \cdot \frac{3}{4} = \frac{15}{40} = \frac{3}{8} \] ### Step 2: Calculate the regression coefficient \( b_{xy} \) The formula for the regression coefficient \( b_{xy} \) is: \[ b_{xy} = r \cdot \frac{\sigma_x}{\sigma_y} \] Substituting the values: \[ b_{xy} = 0.5 \cdot \frac{4}{3} = \frac{5}{10} \cdot \frac{4}{3} = \frac{20}{30} = \frac{2}{3} \] ### Step 3: Write the regression equation of \( y \) on \( x \) The regression equation of \( y \) on \( x \) is given by: \[ y - \bar{y} = b_{yx} (x - \bar{x}) \] Where: - \( \bar{y} = 20 \) - \( \bar{x} = 25 \) Substituting the values: \[ y - 20 = \frac{3}{8} (x - 25) \] ### Step 4: Substitute \( x = 10 \) into the regression equation Now we substitute \( x = 10 \) into the regression equation: \[ y - 20 = \frac{3}{8} (10 - 25) \] Calculating the right side: \[ y - 20 = \frac{3}{8} \cdot (-15) = -\frac{45}{8} \] ### Step 5: Solve for \( y \) Now, we solve for \( y \): \[ y = 20 - \frac{45}{8} \] To combine these terms, convert 20 into eighths: \[ 20 = \frac{160}{8} \] Thus: \[ y = \frac{160}{8} - \frac{45}{8} = \frac{115}{8} \] ### Final Answer The value of \( y \) when \( x = 10 \) is: \[ y = \frac{115}{8} \] ---
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