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Three chairs and two tables costs Rs. 1850. Five chairs and three tables costs Rs. 2850. Find the cost of four chairs and one table by using matrices.

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To solve the problem of finding the cost of four chairs and one table using matrices, we can follow these steps: ### Step 1: Set up the equations Let the cost of one chair be Rs. \( x \) and the cost of one table be Rs. \( y \). We can set up the following equations based on the information provided: 1. For three chairs and two tables costing Rs. 1850: \[ 3x + 2y = 1850 \quad \text{(Equation 1)} \] 2. For five chairs and three tables costing Rs. 2850: \[ 5x + 3y = 2850 \quad \text{(Equation 2)} \] ### Step 2: Represent the equations in matrix form We can represent the above equations in matrix form as \( Ax = b \), where: \[ A = \begin{pmatrix} 3 & 2 \\ 5 & 3 \end{pmatrix}, \quad x = \begin{pmatrix} x \\ y \end{pmatrix}, \quad b = \begin{pmatrix} 1850 \\ 2850 \end{pmatrix} \] ### Step 3: Find the inverse of matrix \( A \) To find \( x \), we need to compute the inverse of matrix \( A \). The formula for the inverse of a 2x2 matrix \( \begin{pmatrix} a & b \\ c & d \end{pmatrix} \) is: \[ A^{-1} = \frac{1}{ad - bc} \begin{pmatrix} d & -b \\ -c & a \end{pmatrix} \] Calculating the determinant of \( A \): \[ \text{det}(A) = (3)(3) - (5)(2) = 9 - 10 = -1 \] Now, we can find the adjoint of \( A \): \[ \text{adj}(A) = \begin{pmatrix} 3 & -2 \\ -5 & 3 \end{pmatrix} \] Thus, the inverse of \( A \) is: \[ A^{-1} = \frac{1}{-1} \begin{pmatrix} 3 & -2 \\ -5 & 3 \end{pmatrix} = \begin{pmatrix} -3 & 2 \\ 5 & -3 \end{pmatrix} \] ### Step 4: Multiply \( A^{-1} \) by \( b \) Now we can find \( x \) by multiplying \( A^{-1} \) with \( b \): \[ x = A^{-1}b = \begin{pmatrix} -3 & 2 \\ 5 & -3 \end{pmatrix} \begin{pmatrix} 1850 \\ 2850 \end{pmatrix} \] Calculating the elements: 1. For \( x \): \[ x = -3(1850) + 2(2850) = -5550 + 5700 = 150 \] 2. For \( y \): \[ y = 5(1850) - 3(2850) = 9250 - 8550 = 700 \] Thus, we have: \[ x = 150, \quad y = 700 \] ### Step 5: Find the cost of four chairs and one table Now we can find the cost of four chairs and one table: \[ \text{Cost} = 4x + y = 4(150) + 700 = 600 + 700 = 1300 \] ### Final Answer The cost of four chairs and one table is Rs. **1300**. ---
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