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Verify if the point having positions vector ` 4 hati-11 hatj +2 hatk ` lies on the line ` overset (-)r =( 6 hati -4 hatj +5hatk ) +mu (2hati +7hatj +3hatk ) `

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To verify if the point with position vector \( \mathbf{r_0} = 4 \hat{i} - 11 \hat{j} + 2 \hat{k} \) lies on the line given by the vector equation \[ \mathbf{r} = (6 \hat{i} - 4 \hat{j} + 5 \hat{k}) + \mu (2 \hat{i} + 7 \hat{j} + 3 \hat{k}), \] we need to find a value of \( \mu \) such that \[ \mathbf{r} = \mathbf{r_0}. \] ### Step 1: Set up the equation We can express the equation of the line in terms of its components: \[ \mathbf{r} = (6 + 2\mu) \hat{i} + (-4 + 7\mu) \hat{j} + (5 + 3\mu) \hat{k}. \] ### Step 2: Equate components Now, we will equate the components of \( \mathbf{r} \) with \( \mathbf{r_0} \): 1. For the \( \hat{i} \) component: \[ 6 + 2\mu = 4. \] 2. For the \( \hat{j} \) component: \[ -4 + 7\mu = -11. \] 3. For the \( \hat{k} \) component: \[ 5 + 3\mu = 2. \] ### Step 3: Solve for \( \mu \) Now we will solve each equation for \( \mu \). **From the \( \hat{i} \) component:** \[ 6 + 2\mu = 4 \implies 2\mu = 4 - 6 \implies 2\mu = -2 \implies \mu = -1. \] **From the \( \hat{j} \) component:** \[ -4 + 7\mu = -11 \implies 7\mu = -11 + 4 \implies 7\mu = -7 \implies \mu = -1. \] **From the \( \hat{k} \) component:** \[ 5 + 3\mu = 2 \implies 3\mu = 2 - 5 \implies 3\mu = -3 \implies \mu = -1. \] ### Step 4: Conclusion Since all three components give the same value \( \mu = -1 \), we conclude that the point \( \mathbf{r_0} = 4 \hat{i} - 11 \hat{j} + 2 \hat{k} \) lies on the line defined by the given vector equation.
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Find the vector equations of the line passing through the point having positions vector -hati -hatj +2hatk and parallel to the line overset(-) r = ( hati+ 2hatj + 3hatk ) +mu (3hati + 2hatj +hatk) , mu is a parameter .

The cartesian equation of a line passing through the point having position vector 2hati +hatj - hatk and parallel to the line passing joining the points -hati + hatj + 4hatk and hati + 2hatj + 2hatk , is

(i) Find the distance of the point (-1,-5,-10) from the point of intersection of the line vec(r) = (2 hati - hatj + 2 hatk ) + lambda (3 hati + 4 hatj + 12 hatk) and the plane vec(r).(hati - hatj + hatk) = 5. (ii) Find the distance of the point with position vector - hati - 5 hatj - 10 hatk from the point of intersection of the line vec(r) = (2 hati - hatj + 2 hatk ) + lambda (3 hati + 4 hatj + 12 hatk ) and the plane vec(r). (hati - hatj + hatk)= 5. (iii) Find the distance of the point (2,12, 5) from the point of intersection of the line . vec(r) = 2 hati - 4 hatj + 2 hatk + lambda (3 hati + 4 hatj + 12 hatk ) and the plane vec(r). (hati - 2 hatj + hatk ) = 0.

Find the distance of the point with position vector - hati - 5 hatj - 10 hatk from the point of intersection of the line vec(r) = (2 hati - hatj + 2 hatk) + lambda ( 3 hati + 4 hatj + 12 hatk) with the plane vec(r). (hati - hatj + hatk) = 5 .

Find the angle between the following pairs of lines : (i) vec(r) = 2 hati - 5 hatj + hatk + lambda (3 hati + 2 hatj + 6 hatk ) and vec(r) = 7 hati - 6 hatk + mu (hati + 2 hatj + 2 hatk) (ii) vec(r) = 3 hati + hatj - 2 hatk + lambda (hati - hatj - 2 hatk ) and vec(r) = 2 hati - hatj - 56 hatk + mu (3 hati - 5 hatj - 4 hatk) .

Find the vector and catesian equations of the plane containing the lines : vec(r) = 2 hati + hatj - 3 hatk + lambda (hati + 2 hatj + 5 hatk ) and vec(r) = 3 hati + 3 hatj - 7 hatk + mu (3 hati - 2 hatj + 5 hatk ) .

The shortest distance between the lines r = ( - hati - hatj - hatk ) + lamda ( 7 hati - 6 hatj + hatk ) and r = ( 3 hati + 5 hatj + 7 hatk ) + mu ( hati - 2 hatj + hatk )

The points with position vectors 5hati + 5hatk, -4hati + 3hatj - hatk and 2hati +hatj + 3hatk

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