Find the area enclosed between y = cos x and X-axis between the lines `x = pi//2` & `x le 3pi//2`

the area enclosed between y=3x and y=x^(2) is

Find the area enclosed the curve y=sin x and the X-axis between x=0 and x=pi .

Find area bounded between y = cos^(-1)x and y-axis between y = pi/2 and y = pi .

Find the area enclosed between curve y = x^(2)+2 , x-axis, x = 1 and x = 2 .

Draw a rough sketch of y=sin 2x and determine the area enclosed by the curve. X-axis and the lines x=pi//4 and x=3pi//4 .

Using integration, find the area enclosed by the curve y = cos, y = sin x and x - axis in the interval [0, pi//2] .

Area enclosed by the curve y = sin^(2)x , the X-axis and the lines x=0, x=pi//2 is

Find the area enclosed between the circle x^2+y^2=25 and the straight line x+y=5 .

Find the area included between the curve y=cosx , the x- axis and ordinates x=-pi/2 and x=pi/2

(i) Make a rough sketch of the graph of the function y = sin x, 0 le x le (pi)/(2) and determine the area enclosed between the curve, the x-axis and the line x = (pi)/(2). (ii) Find the area bounded by the curve: (I) y = sin x" "(II) y = cos x bewtween x =0 and x =2pi.