Find the area of the ellipse `x^(2)//1 + y^(2)//4 = 1` , in first quadrant

Find the area of the ellipse x^(2)/64 + y^(2)/36 = 1 .

Find the area of ellipse x^(2)/1 + y^(2)/4 = 1.

What is the area of the ellipse 4x^(2) + 9y^(2) = 1 .

The area of the ellipse (x^(2))/(9)+ (y^(2))/(4)=1 in first quadrant is 6pi sq. units. The ellipse is rotated about its centre in anti-clockwise direction till its major axis coincides with y-axis. Now the area of the ellipse in first quadrant is........ pi sq. units.

Find area of the ellipse 4x ^(2) + 9y ^(2) = 36.

The area bounded by the ellipse x^(2)/4 + y^(2)/25 = 1 is

The area of the ellipse ((x+1)^(2))/(4)+y^(2)=1 falling in the first quadrant is

In Figure,AOBA is the part of the ellipse 9x^(2)+y^(2)=36 in the first quadrant such that OA=2 and OB=6 Find the area between the arc AB and the chord AB.

Find the point (alpha,beta) on the ellipse 4x^(2)+3y^(2)=12, in the first quadrant,so that the area enclosed by the lines y=x,y=beta,x=alpha, and the x -axis is maximum.