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Find the probability of guessing correctly at least nine out of ten answers in a "true" or "false" objective test.

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To find the probability of guessing correctly at least nine out of ten answers in a "true" or "false" objective test, we can follow these steps: ### Step 1: Understand the Problem We need to calculate the probability of getting at least 9 correct answers out of 10 questions, where each question has two possible answers: True (T) or False (F). ### Step 2: Total Possible Outcomes For each question, there are 2 possible answers. Therefore, for 10 questions, the total number of ways to answer them is: \[ 2^{10} \] Calculating this gives: \[ 2^{10} = 1024 \] ### Step 3: Calculate Favorable Outcomes We need to find the number of ways to guess correctly at least 9 answers. This includes two scenarios: guessing exactly 9 correct answers and guessing all 10 correct answers. #### Scenario 1: Guessing Exactly 9 Correct Answers To find the number of ways to get exactly 9 correct answers, we can choose 9 questions to be correct from the 10 questions. The remaining 1 question will be incorrect. The number of ways to choose 9 questions from 10 is given by the binomial coefficient: \[ \binom{10}{9} = 10 \] This means there are 10 ways to guess exactly 9 correct answers. #### Scenario 2: Guessing All 10 Correct Answers There is only 1 way to get all 10 answers correct: \[ \binom{10}{10} = 1 \] ### Step 4: Total Favorable Outcomes Now, we add the number of favorable outcomes from both scenarios: \[ \text{Total favorable outcomes} = \binom{10}{9} + \binom{10}{10} = 10 + 1 = 11 \] ### Step 5: Calculate the Probability The probability of guessing at least 9 correct answers is given by the ratio of favorable outcomes to total outcomes: \[ P(\text{at least 9 correct}) = \frac{\text{Total favorable outcomes}}{\text{Total possible outcomes}} = \frac{11}{1024} \] ### Final Answer Thus, the probability of guessing correctly at least 9 out of 10 answers is: \[ \frac{11}{1024} \] ---
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NAVNEET PUBLICATION - MAHARASHTRA BOARD-QUESTION BANK 2021-BINOMIAL DISTRIBUTION
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  8. For X ~ B(n , P) and P(X=x) = ""^(8)C(x) (1//2)^(x) (1//2)^(8-x) then ...

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  13. If X ~ B (n,p) with n=10 , p = 0.4 the E (X^(2 ))=?

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