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H2S is passed through acidified solution...

`H_2S` is passed through acidified solution of `CuSO_4` and black ppt is formed. This is due to:

A

oxidation of `Cu^+2`

B

reduction of `Cu^+2`

C

oxidation of `Cu^+2` and then reduction

D

Neither oxidation nor reduction of `Cu^+2`

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The correct Answer is:
D
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