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The melting point of RbBr is 682^@C, wit...

The melting point of RbBr is `682^@C`, with that of `NaFis988^@C`. The principal reason that melting point of NaF is much higher than that of RbBr is that:

A

The two crystsls are not isomorphous

B

The molar mass of NaF is smaller than of RbBr

C

The intermolecular distance rc+ra is greater for RbBr than of NaF

D

The bond is RbBr has more covalent character than the bond in NaF

Text Solution

Verified by Experts

The correct Answer is:
C
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