2g of benzoic acid `(C_(6)H_(5)COOH)` dissolved in 25 g of benzene shows a depression in freezing point equal to 1.62 K. Molar depression constant for benzene is 4.9 K kg `mol^-1`. What is the percentage association of acid if it forms double molecules (dimer) in solution ?

Two elements A and B form compounds having molecular formula AB_(2) and AB_(4) When dissolved in 20 g of benzene, 1 g of AB_(2) lowers the freezing point by 2.3 K, whereas 1.0 g of AB_(4) lowers it by 1.3 K. The molar depression constant for benzene is 5.1 K kg mol^-1 . Calculate the atomic mass of A and B.

1g of a non-electrolyte when dissolved in 50g benzene, the freezing point of solvent is lowered by 0.40K. Find molecular mass of solute. ( K_f for benzene is 5.12 K kg mol^-1 )

15 gm of a substance dissolved in 450 gms of water produces a depression of -0.34^@ C in the freezing point . Calulation the Mol. Wt. of the solid ( K_f for water is 1.86 K kg mol ^(-1) )

0.1 mol sugar was dissolved in 1 Kg water, and depression in freezing point was found to be 0.186K. (K_f for water = 1.86 K Kg mol^(-1) ) .predict whether sugar is dissociated or associated?

0.48g of a non volatile solute was dissolved in 10.6g benzene. The freezing point of the solution was lowered by 1.8^@ C. calculate molecular mass of the salute ( K_f for benzene is 5kgmol^(-1) )

A solution of 1.25 g of a non-electrolyte in 20 g of water freezing at 271.9K with its molal depression constant , then the molecular wt. of the solute is:

The depression in freezing point of a 0.1 molal solution of benzoic acid in benzene is 0.256K. (K_f for benzene =5.12K kg mol^(-1) ) . Calculate the value of van’t Hoff factor and predict whether benzoic acid is associated or dissociated.