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E^(@) values of Mg^(2+) //Mg is -2.37V, ...

`E^(@)` values of `Mg^(2+) //Mg` is -2.37V, of `Zn^(2+)//Zn` is -0.76V and `Fe^(2+) //Fe` is -0.44V.
Which of the following statement is correct ?

A

`Mg` oxidises `Fe`

B

`Zn` oxidises `Fe`

C

`Zn` reduces `Mg^(2+)`

D

`Zn` reduces `Fe^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
D
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For the cell prepared from electrode A and B: Electrode A:Cr_2O_7^(2-)|Cr^(3+),E_(red)^@ =+1.33 V and Electrode B:Fe^(3+) / Fe^(2+),E_(red)^@=0.77 V. Which of the following statements are correct :

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E^@ for Fe^(2+) +2e rarrFe is -0.44 volt and E^@ for Zn^(2+) +2e rarrZn is -0.76 volt thus:

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Consider the standard potential of the following cells, (i) Mg^(2+) +2e rarr Mg,E^@=-2.37V (ii) Zn^(2+) + 2erarrZn,E^@ =-0.76V (iii) Ni^(2+) +2e rarrNi,E^@=-0.25V (iv) Fe^(3+) + 3e rarrFe, E_0=-0.04 V find the strongest reducing agent :

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