molar conductance of 1.5 M solution of an electrolyte is 138.9 `S cm^(2) Mol^(-1)`. Find the specific conductance.

The specific conductance of a 0.12N solution of an electrolyte is 2.4xx10^-2 ohm^-1cm^-1 Calculate its equivalent conductance.

The equivalent conductance of 0.001N KCl solutin is 147 ohm^-1cm^2gm eq^-1 at 25^@C . Find the specific conductance.

Resistance of 0.2 M solution of an electrolyte is 50 Omega . The specific conductance of the solution is 1.3 S m^(-1) . If resistance of the 0.4 M solution of the same electrolyte is 260 Omega , its molar conductivity is

Specific conductance of a 0.12 N solution of electrolyte is 2.4 xx 10^(-2) "ohm^(-1) cm^(-1) . What is the value of its equivalent conductance?

The resistance of a conductivity cell when filled with 0.05M solution of an electrolyte x is 100 Omega at 40^(@)C . The same conductivity cell filled with 0.01M solution of electrolyte y has a resistance of 50 Omega . The conductivity of 0.05 M solution of electrolyte x is 1.0 xx 10^(-4) S cm^(-1) . Calculate (i) cell constant (ii) conductivity of 0.01 M solution (iii) molar conductivity of 0.01 M solution

The Lambda_(m)^(@) values for NaCl and KCl are 126.5 and 149.9 Omega^(-1) cm^(2) "mol"^(-1) respectively. The ionic conductance of Na^(+) at infinite dilution is 50.1 Omega^(-1) cm^(2) "mol"^(-1) . Calculate the ionic conductance at infinite dilution for potassium ion ( K^(+)) .

The specific conductance of solution of 0.12 N is 0.024 mho^(-1) cm^(-1) . Determine its equivalent conductance.

Which of the following electrolytic solutions has the least specific conductance ?