`C_(3)^(2n):C_(3)^(n)= 44:5`, find the value of `n`.

Two moles of NH_3 are introduced into one litre flask in which it dissociates at high temperature as 2NH_3(g) hArr N_2(g) + 3H_2(g) Find the value of K_C .

Solve ""^(2n)C_3:""^nC_3=44:5

If f(x) = (3x+2)^100 and f ' (x) = n(3x+2)^99 then what is the value of n ?

For the reversible reaction N_2(g) + 3H_2(g) = 2NH_3(g) at 500^@C the value of K_p is 1.44 xx 10^-5 when partial pressure measured in atmosphere The corrosponding value of K_c with concentration is mole/lit. IS :

If P(n-1,3):P(n+1,3)=5:12 , find n.

If a_1, a_2,........,a_n are in G.P. and a_i gt 0 for every i, then find the value of [[loga_n, loga_(n+1),loga_(n+2)],[loga_(n+1),loga_(n+2),loga_(n+3)],[loga_(n+2),loga_(n+3),loga_(n+4)]]

If P(n-1,3):P(n+1,3)=5:12,"Find "n .

7^(2n) + 2^(3n-3) 3^(n-1) is divisible by 25 for any natural number n gt 1 .

An organic compound A having molecular formula C_(2)H_(5)O_(2)N on treatment with HNO_(2) gives a blue coloured compound B having molecular formula C_(2)H_(4)O_(3)N_(2) . On reduction, A gives a compound C having molecular formula C_(2)H_(7)N . C on treatment with nitrous acid gives D which gives positive iodoform test. Identify the compounds A, B, C and D.

Find the value of (-i)^(4n+3), when n is positive.