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If the line (x-3)/2=(y+k)/(-1)=(z+1)/(-5...

If the line `(x-3)/2=(y+k)/(-1)=(z+1)/(-5)` lies on the plane 2x-y+z-7 = 0,
then k = -` (2,-1,-2)`

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Proved that the line (x-1)/2=(y+2)/(-3)=(z-3)/1 lies on the plane 7x+5y+z=0

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