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When radiation of the wavelength lamdais...

When radiation of the wavelength `lamda`is incident on a metallic surface ,the stopping potential is 4.8 V. If the same surface is illuminated with radiation of double the wavelength ,then the stopping potential becomes 1.6 V.Then the threshold wavelength for the surface is

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When radiation of wavelength lambda is incident on a metallic surface , the stopping potential is 4.8 "volts" . If the same surface is illuminated with radiation of double the wavelength , then the stopping potential becomes 1.6 "volts" . Then the threshold wavelength for the surface is

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When a metallic surface is illuminated with radiation of wavelength lamda , the stopping potential is V . If the same surface is illuminated with radiation of wavelength 2lamda , the stopping potential is V/4 . The threshold wavelength for the metallic surface is

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When a metalic surface is illuminated with light of wavelength lambda, the stopping potential is V. the same surface is illuminated by light of wavelength 2lambda the stopping potential is (V)/(3) The thershold waelength for the surface is

When a metallic surface of threshold wavelength 4lamda is illuminated with light of wavelength lamda the stopping potential is V. When the same surface is illuminated by the light of wavelength 2lamda Stopping potential is V/3 Threshold wavelength for the metallic surface is