The acceleration a in "m/s^(2)" of a particle is given by,a=3t^(2)+2t+2 where t is the time.If the particle starts out with a velocity u=2m/s at t=0then the velocity at the end of 2 second is

The acceleration a in ms^-2 of a particle is given by a=3t^2+2t+2 , where t is the time. If the particle starts out with a velocity v=2ms^-1 at t=0 , then find the velocity at the end of 2s .

[" The acceleration ' "a" ' (in "m/s^(2)" ) of a particle is "],[" given by "a=3t^(2)+2t-2" ,where "t" is time in "],[" second.If the particle starts with "10m/s" at "t=],[0" ,then the velocity at "t=2s" is "]

The acceleration of a particle varies with time t as a=t^(2)+t+2 where t is in seconds. The particle starts with an initial velocity v-3m/s at t=0. find the velocity of the particle at the end of 5s.

The acceleration a of a particle in m/s^2 is give by a=18t^2+36t+120 . If the particle starts from rest, then velocity at end of 1 s is

If velocity of a particle is given by v=2t^(2)-2 then find the acceleration of particle at t = 2 s.

The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.

Acceleration of a particle is given by a= 3t^(2)+2t +1 Where t is time . Find (i) its velocity at time t assuming velocity to be 10 m/s at t = 0. (ii) its position at time t assuming that the particle is at origin at t = 0. (iii) What is the average speed of the particle in the duration t = 0 to t = 1s? (iv) What is the average acceleration of the particle in the duration t = 0 to t = 1s?

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :