If the wavelength of the first member of Balmer series of hydrogen spectrum is `6564A^(@)` , the wavelength of second member of Balmer series will be:

If the wavelength of the first member of Blmer series of hydrogen spectrum is 6563Å A, then the wavelength of second member of Blamer series will be

If the wavelength of the first member of Balmer series in hydrogen spectrum is 6563 Å, calculate the wavelength of the first member of Lymen series in the same spectrum.

The wavelength of the first lime of the Lyman series of hydrogen is 121.6 nm. The wavelength of the second member of the Balmer series is

The wavelength of the first member of the balmer series of hydrogen is 6563xx10^(-10)m . Calculate the wavelength of its second member.

Calculate the wavelength of the first line in the balmer series of hydrogen spectrum

If the wavelength of the first line of the Balmer series of hydrogen is 6561 Å , the wavelngth of the second line of the series should be

If the wavelength of the first line of the Balmer series of hydrogen atom is 656.1 nm the wavelngth of the second line of this series would be

The wavelength of the third line of the Balmer series for a hydrogen atom is -

The Wavelength of first member of Balmer series in hydrogen spectrum is lambda . Calculate the wavelength of first member of Lymen series in the same spectrum