Time period of a simple pendulum of length L is `T_(1)` and time period of a uniform rod of the same length L pivoted about an end and oscillating in a vertical plane is `T_(2)`. Amplitude of osciallations in both the cases is small. Then `T_(1)/T_(2)` is

Time period of is simple pendulum of length L is T_(1) and the point time peirod of a uniform rod of the same length L pivotal about one end and oscillating in vertical plane is T_(2) . Amplitude of oscillation in both the cased is small. The T_(1)//T_(2) is:

Find the period of small oscillations of a uniform rod with length l , pivoted at one end.

A thin uniform rod of length l is pivoted at its upper end. It is free to swing in a vertical plane. Its time period for oscillation of small amplitude is

The time period of simple pendulum is T. If its length is increased by 2%, the new time period becomes

Time period T of a simple pendulum of length l is given by T = 2pisqrt((l)/(g)) . If the length is increased by 2% then an approximate change in the time period is

The graph of time period (T) of a simple pendulum versus its length (I) is

A simple pendulum has time period T. A uniform rod, whose length is the same as that of the pendulum, undergoes small oscillations about its upper end. Its time period of oscillation will be -

For a simple pendulum, the graph between T^(2) and L (where T is the time period & Lis the length) is