The angular velocity of the earth with which it has to rotate so that the acceleration due to gravity on `60^@` latitude becomes zero is

Acceleration due to gravity of earth

At the centre of earth the acceleration due to gravity is

The acceleration due to gravity at the equator becomes zero, if

At what depth the acceleration due to gravity becomes zero ?

Calculate angular velocity of the earth so that acceleration due to gravity at 60^(@) latitude becomes zero (radius of the earth = 6400 km, gravitational acceleration at poles = 10 m//s^(2) , cos60^(@) = 0.5 )

Let omega be the angular velocity of the earth's rotation about its axis. Assume that the acceleration due to gravity on the earth's surface has the same value at the equator and the poles. An object weighed at the equator gives the same reading as a reading taken at a depth d below earth's surface at a pole (dlt ltR) . the value of d is-

Let omega be the angular velocity of the earth's rotation about its axis. Assume that the acceleration due to gravity on the earth's surface has the same value at the equator and the poles. An object weighed by a spring balance gives the same reading at the equator as at a height h above the poles (h lt lt R) . The value of h is

Questions based on acceleration due to gravity of earth

At the centre of the earth , the value of the acceleration due to gravity becomes zero.