In a series CR circuit shown in figure,the applied voltage is 10V and the voltage across capacitor is found to be 8V

In a series C-R circuit shown in figureure, the applied voltage is 10 V and the voltage across capacitor is found to 8 V . The voltage across R , and the phase difference between current and the applied voltage will respectively be .

In the circuit shown in the figure, the total charge is 750 mu C and the voltage across capacitor C_2 is 20 V. Then the charge on capacitor C_2 is:

In the circuit shown in figure, Voltage V_(0) is

In the circuit shown in figure, Voltage V_0 is–

In the circuit shown in figure, the final voltage drop across the capacitor C is :

In the circuit shown in figure the maximum output voltage V_(0) is

In a series L-C circuit, the applied voltage is V_0. if omega is very low, then the voltage drop across the inductor V_L and capacitor V_C are .

In a series L-C-R circuit, currenrt in the circuit is 11A when the applied voltage is 220 V . voltage across the caspcitor is 200 V . If the value of resistor is 20 Omega , then the voltage across the unknown inductor is

In the series L-C-R circuit shown in the figure, the rms voltage across the resistor and inductor are 400 V and 700 V respectively. If the applied voltage is E=500sqrt(2)sin(omega t) , then the peak voltage across the capacitor is